Calculate the sum of diagonal elements of a matrix

we are given a square matrix of order NxN and we have to find the sum of diagonal elements of the given matrix.
so we have to sum all elements of the left diagonal and the sum of all elements of the right diagonal of a matrix.

Input: Matrix = [[7,1,5],[1,2,3],[4,0,6]]
Output: 20

Here in this example, we are given a 2D array we get a sum of diagonals as output.

Sum of Left Diagonal elements = 9

sum of right diagonal elements = 11

The total sum of diagonal element = 20

Let us understand the logic before going to a solution.
we know that all the elements of the left diagonal are like
(i=j).
and condition for the right diagonal element is ( i+j=N-1).
where i and j are position coordinates and N is the size of Matrix.

Sum of diagonal of the matrix in C++

Here is the implementation of the sum of diagonal elements of the matrix in c++.

int main()
{
int Matrix[3][3]; //get element form user
int N= sizeof(Matrix);
for(int i=0; i<N ; i++){
    for(int j=0; j<N; j++){
      cin >> matrix[i][j];
      if(i==j)
        sumL =sumL + matrix[i][j];
      if((i+j) == N-1)
        sumR = sumR + matrix[i][j];
    }
  }
  cout<<sumR +sumL;
  return 0;
  }

Sum of diagonal of the matrix in Java

Here is the implementation of the sum of diagonal elements of the matrix in the Java programming language.

class Solution {
    public int SumDiagonal(int[][] Matrix) {
        int N=Matrix.length;
        for(int i=0; i<N ; i++){
    for(int j=0; j<N; j++){
      cin >> matrix[i][j];
      if(i==j)
        sumL =sumL + matrix[i][j];
      if((i+j) == N-1)
        sumR = sumR + matrix[i][j];
    }
  }
  
return sumR+sumL;
        
    }
}

Sum of diagonal of the matrix in Python

here is the implementation of the sum of diagonal elements of a 2D array in Python.

Matrix=[[0]*M]*M
sum=0
for i in range(M):
    for j in range(M):
        if i==j:
            sum=sum+Matrix[i][j]
        elif i+j=M-1:
            sum=sum+Matrix[i][j]
print(sum)